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How many grams of HCl (36.5 g/mol) must be used to produce 10 L of chlorine at STP?
c. 32.6 g Chlorine is produced by the reaction 2HCl(g) → H2(g) + Cl2(g). 32.6 grams of HCl (36.5 g/mol) must be used to produce 10 L of chlorine at STP.
c. 32.6 g
Chlorine is produced by the reaction 2HCl(g) → H2(g) + Cl2(g). 32.6 grams of HCl (36.5 g/mol) must be used to produce 10 L of chlorine at STP.
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